Base | Representation |
---|---|
bin | 100000001010010010… |
… | …011011000110100011 |
3 | 10022010121200122012102 |
4 | 200022102123012203 |
5 | 1031210234341011 |
6 | 23510335521015 |
7 | 2331513022322 |
oct | 401222330643 |
9 | 108117618172 |
10 | 34532340131 |
11 | 13710673283 |
12 | 683898916b |
13 | 3344382a73 |
14 | 19583720b9 |
15 | d719a473b |
hex | 80a49b1a3 |
34532340131 has 2 divisors, whose sum is σ = 34532340132. Its totient is φ = 34532340130.
The previous prime is 34532340119. The next prime is 34532340133. The reversal of 34532340131 is 13104323543.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34532340131 - 230 = 33458598307 is a prime.
It is a super-2 number, since 2×345323401312 (a number of 22 digits) contains 22 as substring.
Together with 34532340133, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 34532340094 and 34532340103.
It is not a weakly prime, because it can be changed into another prime (34532340133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17266170065 + 17266170066.
It is an arithmetic number, because the mean of its divisors is an integer number (17266170066).
Almost surely, 234532340131 is an apocalyptic number.
34532340131 is a deficient number, since it is larger than the sum of its proper divisors (1).
34532340131 is an equidigital number, since it uses as much as digits as its factorization.
34532340131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 29.
Adding to 34532340131 its reverse (13104323543), we get a palindrome (47636663674).
The spelling of 34532340131 in words is "thirty-four billion, five hundred thirty-two million, three hundred forty thousand, one hundred thirty-one".
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