Base | Representation |
---|---|
bin | 1111101101010010000110… |
… | …00011111110011100011111 |
3 | 11112022010000020201111022211 |
4 | 13312221003003332130133 |
5 | 14011410441020010421 |
6 | 201244010540221251 |
7 | 10163344266414415 |
oct | 766510303763437 |
9 | 145263006644284 |
10 | 34541252110111 |
11 | 10007954366aaa |
12 | 3a5a3ab53a827 |
13 | 16372c2976156 |
14 | 875b3c4d32b5 |
15 | 3ed76d27e9e1 |
hex | 1f6a430fe71f |
34541252110111 has 2 divisors, whose sum is σ = 34541252110112. Its totient is φ = 34541252110110.
The previous prime is 34541252110097. The next prime is 34541252110117. The reversal of 34541252110111 is 11101125214543.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 34541252110111 - 29 = 34541252109599 is a prime.
It is a super-3 number, since 3×345412521101113 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34541252110117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17270626055055 + 17270626055056.
It is an arithmetic number, because the mean of its divisors is an integer number (17270626055056).
Almost surely, 234541252110111 is an apocalyptic number.
34541252110111 is a deficient number, since it is larger than the sum of its proper divisors (1).
34541252110111 is an equidigital number, since it uses as much as digits as its factorization.
34541252110111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 31.
Adding to 34541252110111 its reverse (11101125214543), we get a palindrome (45642377324654).
The spelling of 34541252110111 in words is "thirty-four trillion, five hundred forty-one billion, two hundred fifty-two million, one hundred ten thousand, one hundred eleven".
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