Base | Representation |
---|---|
bin | 100111010001011111011001… |
… | …1111111100000001001101111 |
3 | 1200022010211210101112110211121 |
4 | 1032202332303333200021233 |
5 | 330234334220243244012 |
6 | 3222414124413201411 |
7 | 132523023026136145 |
oct | 11642766377401157 |
9 | 1608124711473747 |
10 | 345451534353007 |
11 | a008719a26a635 |
12 | 328b29a3a90267 |
13 | 11a9ac2aca1274 |
14 | 6143d2cc73595 |
15 | 29e0ec1abda07 |
hex | 13a2fb3fe026f |
345451534353007 has 2 divisors, whose sum is σ = 345451534353008. Its totient is φ = 345451534353006.
The previous prime is 345451534352983. The next prime is 345451534353119. The reversal of 345451534353007 is 700353435154543.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-345451534353007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (345451534353707) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172725767176503 + 172725767176504.
It is an arithmetic number, because the mean of its divisors is an integer number (172725767176504).
Almost surely, 2345451534353007 is an apocalyptic number.
345451534353007 is a deficient number, since it is larger than the sum of its proper divisors (1).
345451534353007 is an equidigital number, since it uses as much as digits as its factorization.
345451534353007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 22680000, while the sum is 52.
The spelling of 345451534353007 in words is "three hundred forty-five trillion, four hundred fifty-one billion, five hundred thirty-four million, three hundred fifty-three thousand, seven".
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