Base | Representation |
---|---|
bin | 100111010010000110100001… |
… | …1110010111010010100011111 |
3 | 1200022102212122200100010211201 |
4 | 1032210031003302322110133 |
5 | 330242223302121200142 |
6 | 3222520501345100331 |
7 | 132532056035625322 |
oct | 11644150362722437 |
9 | 1608385580303751 |
10 | 345535551350047 |
11 | a0109893709a83 |
12 | 329071310276a7 |
13 | 11aa5b2a3c90b6 |
14 | 614801d3087b9 |
15 | 29e328ca6dab7 |
hex | 13a4343cba51f |
345535551350047 has 2 divisors, whose sum is σ = 345535551350048. Its totient is φ = 345535551350046.
The previous prime is 345535551349997. The next prime is 345535551350131. The reversal of 345535551350047 is 740053155535543.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 345535551350047 - 239 = 344985795536159 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 345535551350047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (345535551360047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 172767775675023 + 172767775675024.
It is an arithmetic number, because the mean of its divisors is an integer number (172767775675024).
Almost surely, 2345535551350047 is an apocalyptic number.
345535551350047 is a deficient number, since it is larger than the sum of its proper divisors (1).
345535551350047 is an equidigital number, since it uses as much as digits as its factorization.
345535551350047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 47250000, while the sum is 55.
The spelling of 345535551350047 in words is "three hundred forty-five trillion, five hundred thirty-five billion, five hundred fifty-one million, three hundred fifty thousand, forty-seven".
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