Base | Representation |
---|---|
bin | 100000001110111011… |
… | …111101111001011001 |
3 | 10022100001110102002212 |
4 | 200032323331321121 |
5 | 1031340221330132 |
6 | 23522203404505 |
7 | 2333451013433 |
oct | 401673757131 |
9 | 108301412085 |
10 | 34610339417 |
11 | 137506a82a5 |
12 | 685ab23735 |
13 | 33575925a4 |
14 | 1964877653 |
15 | d787605b2 |
hex | 80eefde59 |
34610339417 has 2 divisors, whose sum is σ = 34610339418. Its totient is φ = 34610339416.
The previous prime is 34610339381. The next prime is 34610339419. The reversal of 34610339417 is 71493301643.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 30145293376 + 4465046041 = 173624^2 + 66821^2 .
It is an emirp because it is prime and its reverse (71493301643) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 34610339417 - 212 = 34610335321 is a prime.
Together with 34610339419, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (34610339419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17305169708 + 17305169709.
It is an arithmetic number, because the mean of its divisors is an integer number (17305169709).
Almost surely, 234610339417 is an apocalyptic number.
It is an amenable number.
34610339417 is a deficient number, since it is larger than the sum of its proper divisors (1).
34610339417 is an equidigital number, since it uses as much as digits as its factorization.
34610339417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 163296, while the sum is 41.
The spelling of 34610339417 in words is "thirty-four billion, six hundred ten million, three hundred thirty-nine thousand, four hundred seventeen".
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