Base | Representation |
---|---|
bin | 110010011110110100001… |
… | …011001110000100001011 |
3 | 110021122020212010200221101 |
4 | 302132310023032010023 |
5 | 423314114212313242 |
6 | 11213355334122231 |
7 | 505426401531304 |
oct | 62366413160413 |
9 | 13248225120841 |
10 | 3469061447947 |
11 | 1118247827097 |
12 | 4803b17b0377 |
13 | 1c2192011734 |
14 | bdc9119b7ab |
15 | 603891589b7 |
hex | 327b42ce10b |
3469061447947 has 2 divisors, whose sum is σ = 3469061447948. Its totient is φ = 3469061447946.
The previous prime is 3469061447893. The next prime is 3469061447977. The reversal of 3469061447947 is 7497441609643.
3469061447947 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3469061447947 is a prime.
It is not a weakly prime, because it can be changed into another prime (3469061447977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1734530723973 + 1734530723974.
It is an arithmetic number, because the mean of its divisors is an integer number (1734530723974).
Almost surely, 23469061447947 is an apocalyptic number.
3469061447947 is a deficient number, since it is larger than the sum of its proper divisors (1).
3469061447947 is an equidigital number, since it uses as much as digits as its factorization.
3469061447947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 109734912, while the sum is 64.
The spelling of 3469061447947 in words is "three trillion, four hundred sixty-nine billion, sixty-one million, four hundred forty-seven thousand, nine hundred forty-seven".
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