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34701621695989 is a prime number
BaseRepresentation
bin1111110001111100110011…
…10101011001010111110101
311112212102221200101112211121
413320332121311121113311
514022022410123232424
6201445412133103541
710211052351410443
oct770763165312765
9145772850345747
1034701621695989
1110069969861536
123a854a6a87bb1
13164946c665a31
1487d7d3131b93
15402a073c3ee4
hex1f8f99d595f5

34701621695989 has 2 divisors, whose sum is σ = 34701621695990. Its totient is φ = 34701621695988.

The previous prime is 34701621695887. The next prime is 34701621696013. The reversal of 34701621695989 is 98959612610743.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34279327071025 + 422294624964 = 5854855^2 + 649842^2 .

It is a cyclic number.

It is not a de Polignac number, because 34701621695989 - 211 = 34701621693941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34701621665989) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17350810847994 + 17350810847995.

It is an arithmetic number, because the mean of its divisors is an integer number (17350810847995).

It is a 1-persistent number, because it is pandigital, but 2⋅34701621695989 = 69403243391978 is not.

Almost surely, 234701621695989 is an apocalyptic number.

It is an amenable number.

34701621695989 is a deficient number, since it is larger than the sum of its proper divisors (1).

34701621695989 is an equidigital number, since it uses as much as digits as its factorization.

34701621695989 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 176359680, while the sum is 70.

The spelling of 34701621695989 in words is "thirty-four trillion, seven hundred one billion, six hundred twenty-one million, six hundred ninety-five thousand, nine hundred eighty-nine".