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347444552124113 is a prime number
BaseRepresentation
bin100111011111111111011110…
…1000110111100011011010001
31200120012101010020002100101112
41032333332331012330123101
5331020012420320432423
63230541453532543105
7133120016616521603
oct11677767506743321
91616171106070345
10347444552124113
11a07854528a4514
1232b750b9621a95
1311bb3b5ab12442
1461b25982b1173
152a27c6bae2a78
hex13bffbd1bc6d1

347444552124113 has 2 divisors, whose sum is σ = 347444552124114. Its totient is φ = 347444552124112.

The previous prime is 347444552124097. The next prime is 347444552124133. The reversal of 347444552124113 is 311421255444743.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 323364264158224 + 24080287965889 = 17982332^2 + 4907167^2 .

It is an emirp because it is prime and its reverse (311421255444743) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 347444552124113 - 24 = 347444552124097 is a prime.

It is not a weakly prime, because it can be changed into another prime (347444552124133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 173722276062056 + 173722276062057.

It is an arithmetic number, because the mean of its divisors is an integer number (173722276062057).

Almost surely, 2347444552124113 is an apocalyptic number.

It is an amenable number.

347444552124113 is a deficient number, since it is larger than the sum of its proper divisors (1).

347444552124113 is an equidigital number, since it uses as much as digits as its factorization.

347444552124113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6451200, while the sum is 50.

The spelling of 347444552124113 in words is "three hundred forty-seven trillion, four hundred forty-four billion, five hundred fifty-two million, one hundred twenty-four thousand, one hundred thirteen".