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3480051125647 is a prime number
BaseRepresentation
bin110010101001000011001…
…101100000110110001111
3110022200121202011011122101
4302221003031200312033
5424004121042010042
611222414033055531
7506265624333055
oct62510315406617
913280552134571
103480051125647
111121977154658
1248255a0b75a7
131c3223a638c5
14c06149421d5
15607cdd596b7
hex32a43360d8f

3480051125647 has 2 divisors, whose sum is σ = 3480051125648. Its totient is φ = 3480051125646.

The previous prime is 3480051125569. The next prime is 3480051125651. The reversal of 3480051125647 is 7465211500843.

It is a strong prime.

It is an emirp because it is prime and its reverse (7465211500843) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3480051125647 is a prime.

It is a super-2 number, since 2×34800511256472 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3480051125597 and 3480051125606.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3480051125687) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740025562823 + 1740025562824.

It is an arithmetic number, because the mean of its divisors is an integer number (1740025562824).

Almost surely, 23480051125647 is an apocalyptic number.

3480051125647 is a deficient number, since it is larger than the sum of its proper divisors (1).

3480051125647 is an equidigital number, since it uses as much as digits as its factorization.

3480051125647 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 806400, while the sum is 46.

The spelling of 3480051125647 in words is "three trillion, four hundred eighty billion, fifty-one million, one hundred twenty-five thousand, six hundred forty-seven".