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3480724114793 is a prime number
BaseRepresentation
bin110010101001101011010…
…100110000110101101001
3110022202100122111120012022
4302221223110300311221
5424012010333133133
611223004513354225
7506321405545412
oct62515324606551
913282318446168
103480724114793
111122192025332
12482707568975
131c3300306733
14c067a088809
156081ce93998
hex32a6b530d69

3480724114793 has 2 divisors, whose sum is σ = 3480724114794. Its totient is φ = 3480724114792.

The previous prime is 3480724114787. The next prime is 3480724114837. The reversal of 3480724114793 is 3974114270843.

3480724114793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3080474296384 + 400249818409 = 1755128^2 + 632653^2 .

It is a cyclic number.

It is not a de Polignac number, because 3480724114793 - 28 = 3480724114537 is a prime.

It is not a weakly prime, because it can be changed into another prime (3480724114723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1740362057396 + 1740362057397.

It is an arithmetic number, because the mean of its divisors is an integer number (1740362057397).

Almost surely, 23480724114793 is an apocalyptic number.

It is an amenable number.

3480724114793 is a deficient number, since it is larger than the sum of its proper divisors (1).

3480724114793 is an equidigital number, since it uses as much as digits as its factorization.

3480724114793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4064256, while the sum is 53.

The spelling of 3480724114793 in words is "three trillion, four hundred eighty billion, seven hundred twenty-four million, one hundred fourteen thousand, seven hundred ninety-three".