Base | Representation |
---|---|
bin | 110010101011111100001… |
… | …101011100010010111011 |
3 | 110022222122001102211121101 |
4 | 302223330031130102323 |
5 | 424032000123020323 |
6 | 11224050025352231 |
7 | 506435553035335 |
oct | 62537415342273 |
9 | 13288561384541 |
10 | 3483154891963 |
11 | 112321a14918a |
12 | 483085638677 |
13 | 1c35c9aaa016 |
14 | c082ac3a455 |
15 | 60911598dad |
hex | 32afc35c4bb |
3483154891963 has 2 divisors, whose sum is σ = 3483154891964. Its totient is φ = 3483154891962.
The previous prime is 3483154891871. The next prime is 3483154891967. The reversal of 3483154891963 is 3691984513843.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3483154891963 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3483154891895 and 3483154891904.
It is not a weakly prime, because it can be changed into another prime (3483154891967) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1741577445981 + 1741577445982.
It is an arithmetic number, because the mean of its divisors is an integer number (1741577445982).
Almost surely, 23483154891963 is an apocalyptic number.
3483154891963 is a deficient number, since it is larger than the sum of its proper divisors (1).
3483154891963 is an equidigital number, since it uses as much as digits as its factorization.
3483154891963 is an evil number, because the sum of its binary digits is even.
The product of its digits is 67184640, while the sum is 64.
The spelling of 3483154891963 in words is "three trillion, four hundred eighty-three billion, one hundred fifty-four million, eight hundred ninety-one thousand, nine hundred sixty-three".
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