Base | Representation |
---|---|
bin | 1111110101111011001110… |
… | …10100100001001000100101 |
3 | 11120100111111222100100112102 |
4 | 13322331213110201020211 |
5 | 14031242130032412301 |
6 | 202032242034301445 |
7 | 10223656253651354 |
oct | 772754724411045 |
9 | 146314458310472 |
10 | 34838213169701 |
11 | 101118921163a7 |
12 | 3aa7a67127885 |
13 | 16592ca008066 |
14 | 88626dbb399b |
15 | 40634dc56b6b |
hex | 1faf67521225 |
34838213169701 has 2 divisors, whose sum is σ = 34838213169702. Its totient is φ = 34838213169700.
The previous prime is 34838213169673. The next prime is 34838213169719. The reversal of 34838213169701 is 10796131283843.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28217503360225 + 6620709809476 = 5312015^2 + 2573074^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-34838213169701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (34838213169791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17419106584850 + 17419106584851.
It is an arithmetic number, because the mean of its divisors is an integer number (17419106584851).
Almost surely, 234838213169701 is an apocalyptic number.
It is an amenable number.
34838213169701 is a deficient number, since it is larger than the sum of its proper divisors (1).
34838213169701 is an equidigital number, since it uses as much as digits as its factorization.
34838213169701 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5225472, while the sum is 56.
The spelling of 34838213169701 in words is "thirty-four trillion, eight hundred thirty-eight billion, two hundred thirteen million, one hundred sixty-nine thousand, seven hundred one".
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