34908025343 has 2 divisors, whose sum is σ = 34908025344. Its totient is φ = 34908025342.

The previous prime is 34908025303. The next prime is 34908025351. The reversal of 34908025343 is 34352080943.

34908025343 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (34352080943) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 34908025343 - 2¹⁴ = 34908008959 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 34908025343.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (34908025303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17454012671 + 17454012672.

It is an arithmetic number, because the mean of its divisors is an integer number (17454012672).

Almost surely, 2^34908025343 is an apocalyptic number.

34908025343 is a deficient number, since it is larger than the sum of its proper divisors (1).

34908025343 is an equidigital number, since it uses as much as digits as its factorization.

34908025343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 34908025343 in words is "thirty-four billion, nine hundred eight million, twenty-five thousand, three hundred forty-three".