Search a number
-
+
349131067141 is a prime number
BaseRepresentation
bin1010001010010011101…
…01010100111100000101
31020101011112200211120111
411011021311110330011
521210010023122031
6424215534233021
734136536051213
oct5051165247405
91211145624514
10349131067141
1112507a42721a
12577b7355771
1326bcc86187c
1412c802c1cb3
159135b121b1
hex5149d54f05

349131067141 has 2 divisors, whose sum is σ = 349131067142. Its totient is φ = 349131067140.

The previous prime is 349131067123. The next prime is 349131067151. The reversal of 349131067141 is 141760131943.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 348489508900 + 641558241 = 590330^2 + 25329^2 .

It is a cyclic number.

It is not a de Polignac number, because 349131067141 - 217 = 349130936069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 349131067094 and 349131067103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (349131067151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 174565533570 + 174565533571.

It is an arithmetic number, because the mean of its divisors is an integer number (174565533571).

Almost surely, 2349131067141 is an apocalyptic number.

It is an amenable number.

349131067141 is a deficient number, since it is larger than the sum of its proper divisors (1).

349131067141 is an equidigital number, since it uses as much as digits as its factorization.

349131067141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 40.

The spelling of 349131067141 in words is "three hundred forty-nine billion, one hundred thirty-one million, sixty-seven thousand, one hundred forty-one".