Base | Representation |
---|---|
bin | 1010001011111110001… |
… | …00100000110000001101 |
3 | 1020110110210100201120222 |
4 | 11011333010200300031 |
5 | 21213322201141031 |
6 | 424444322121125 |
7 | 34200632644142 |
oct | 5057704406015 |
9 | 1213423321528 |
10 | 350024240141 |
11 | 125498616324 |
12 | 57a064b01a5 |
13 | 270129079c4 |
14 | 12d26b823c9 |
15 | 9189240e7b |
hex | 517f120c0d |
350024240141 has 2 divisors, whose sum is σ = 350024240142. Its totient is φ = 350024240140.
The previous prime is 350024240131. The next prime is 350024240147. The reversal of 350024240141 is 141042420053.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 323244554116 + 26779686025 = 568546^2 + 163645^2 .
It is an emirp because it is prime and its reverse (141042420053) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 350024240141 - 218 = 350023977997 is a prime.
It is a super-3 number, since 3×3500242401413 (a number of 36 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 350024240141.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (350024240147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175012120070 + 175012120071.
It is an arithmetic number, because the mean of its divisors is an integer number (175012120071).
Almost surely, 2350024240141 is an apocalyptic number.
It is an amenable number.
350024240141 is a deficient number, since it is larger than the sum of its proper divisors (1).
350024240141 is an equidigital number, since it uses as much as digits as its factorization.
350024240141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3840, while the sum is 26.
Adding to 350024240141 its reverse (141042420053), we get a palindrome (491066660194).
The spelling of 350024240141 in words is "three hundred fifty billion, twenty-four million, two hundred forty thousand, one hundred forty-one".
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