Base | Representation |
---|---|
bin | 1111111010110000101001… |
… | …10110010011010001001101 |
3 | 11120221101022011120100122022 |
4 | 13331120110312103101031 |
5 | 14042002333302211141 |
6 | 202240434012055525 |
7 | 10241660003163305 |
oct | 775302466232115 |
9 | 146841264510568 |
10 | 35004333241421 |
11 | 1017628860aa75 |
12 | 3b140a84645a5 |
13 | 166bb8219119b |
14 | 89030c430605 |
15 | 40a822b48b4b |
hex | 1fd614d9344d |
35004333241421 has 2 divisors, whose sum is σ = 35004333241422. Its totient is φ = 35004333241420.
The previous prime is 35004333241417. The next prime is 35004333241429. The reversal of 35004333241421 is 12414233340053.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24222008755396 + 10782324486025 = 4921586^2 + 3283645^2 .
It is an emirp because it is prime and its reverse (12414233340053) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35004333241421 - 22 = 35004333241417 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35004333241429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17502166620710 + 17502166620711.
It is an arithmetic number, because the mean of its divisors is an integer number (17502166620711).
Almost surely, 235004333241421 is an apocalyptic number.
It is an amenable number.
35004333241421 is a deficient number, since it is larger than the sum of its proper divisors (1).
35004333241421 is an equidigital number, since it uses as much as digits as its factorization.
35004333241421 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 35004333241421 its reverse (12414233340053), we get a palindrome (47418566581474).
The spelling of 35004333241421 in words is "thirty-five trillion, four billion, three hundred thirty-three million, two hundred forty-one thousand, four hundred twenty-one".
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