Base | Representation |
---|---|
bin | 100000100110011010… |
… | …111101100011000101 |
3 | 10100100111211201212122 |
4 | 200212122331203011 |
5 | 1033142102343141 |
6 | 24025240255325 |
7 | 2346303661421 |
oct | 404632754305 |
9 | 110314751778 |
10 | 35004340421 |
11 | 13933046066 |
12 | 694aa71545 |
13 | 33bb0b348b |
14 | 19a0d19b81 |
15 | d9d13b64b |
hex | 8266bd8c5 |
35004340421 has 2 divisors, whose sum is σ = 35004340422. Its totient is φ = 35004340420.
The previous prime is 35004340417. The next prime is 35004340477. The reversal of 35004340421 is 12404340053.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33796777921 + 1207562500 = 183839^2 + 34750^2 .
It is a cyclic number.
It is not a de Polignac number, because 35004340421 - 22 = 35004340417 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35004340411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17502170210 + 17502170211.
It is an arithmetic number, because the mean of its divisors is an integer number (17502170211).
Almost surely, 235004340421 is an apocalyptic number.
It is an amenable number.
35004340421 is a deficient number, since it is larger than the sum of its proper divisors (1).
35004340421 is an equidigital number, since it uses as much as digits as its factorization.
35004340421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 26.
Adding to 35004340421 its reverse (12404340053), we get a palindrome (47408680474).
The spelling of 35004340421 in words is "thirty-five billion, four million, three hundred forty thousand, four hundred twenty-one".
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