Base | Representation |
---|---|
bin | 110010111100100001100… |
… | …011101001110110000001 |
3 | 110101200121000102011100111 |
4 | 302330201203221312001 |
5 | 424324432100401201 |
6 | 11240152555351321 |
7 | 510636041252341 |
oct | 62744143516601 |
9 | 13350530364314 |
10 | 3500961340801 |
11 | 112a827452801 |
12 | 486614a52541 |
13 | 1c51a6ba0692 |
14 | c1639a82d21 |
15 | 6110496db51 |
hex | 32f218e9d81 |
3500961340801 has 2 divisors, whose sum is σ = 3500961340802. Its totient is φ = 3500961340800.
The previous prime is 3500961340693. The next prime is 3500961340813. The reversal of 3500961340801 is 1080431690053.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3302579290000 + 198382050801 = 1817300^2 + 445401^2 .
It is a cyclic number.
It is not a de Polignac number, because 3500961340801 - 27 = 3500961340673 is a prime.
It is not a weakly prime, because it can be changed into another prime (3500961340871) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1750480670400 + 1750480670401.
It is an arithmetic number, because the mean of its divisors is an integer number (1750480670401).
Almost surely, 23500961340801 is an apocalyptic number.
It is an amenable number.
3500961340801 is a deficient number, since it is larger than the sum of its proper divisors (1).
3500961340801 is an equidigital number, since it uses as much as digits as its factorization.
3500961340801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 77760, while the sum is 40.
The spelling of 3500961340801 in words is "three trillion, five hundred billion, nine hundred sixty-one million, three hundred forty thousand, eight hundred one".
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