Base | Representation |
---|---|
bin | 110010111100100001100… |
… | …011101001110100010101 |
3 | 110101200121000102011012111 |
4 | 302330201203221310111 |
5 | 424324432100400233 |
6 | 11240152555351021 |
7 | 510636041252125 |
oct | 62744143516425 |
9 | 13350530364174 |
10 | 3500961340693 |
11 | 112a827452713 |
12 | 486614a52471 |
13 | 1c51a6ba060b |
14 | c1639a82c85 |
15 | 6110496dacd |
hex | 32f218e9d15 |
3500961340693 has 2 divisors, whose sum is σ = 3500961340694. Its totient is φ = 3500961340692.
The previous prime is 3500961340691. The next prime is 3500961340801. The reversal of 3500961340693 is 3960431690053.
3500961340693 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3340494600804 + 160466739889 = 1827702^2 + 400583^2 .
It is a cyclic number.
It is not a de Polignac number, because 3500961340693 - 21 = 3500961340691 is a prime.
Together with 3500961340691, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3500961340691) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1750480670346 + 1750480670347.
It is an arithmetic number, because the mean of its divisors is an integer number (1750480670347).
Almost surely, 23500961340693 is an apocalyptic number.
It is an amenable number.
3500961340693 is a deficient number, since it is larger than the sum of its proper divisors (1).
3500961340693 is an equidigital number, since it uses as much as digits as its factorization.
3500961340693 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1574640, while the sum is 49.
The spelling of 3500961340693 in words is "three trillion, five hundred billion, nine hundred sixty-one million, three hundred forty thousand, six hundred ninety-three".
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