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35011000117 is a prime number
BaseRepresentation
bin100000100110110100…
…010111011100110101
310100100222101002021001
4200212310113130311
51033200304000432
624030035123301
72346414406432
oct404664273465
9110328332231
1035011000117
1113936884645
126951143531
1333bc5a5822
1419a1b70b89
15d9da049e7
hex826d17735

35011000117 has 2 divisors, whose sum is σ = 35011000118. Its totient is φ = 35011000116.

The previous prime is 35011000097. The next prime is 35011000151. The reversal of 35011000117 is 71100011053.

35011000117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 34849049041 + 161951076 = 186679^2 + 12726^2 .

It is an emirp because it is prime and its reverse (71100011053) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35011000117 - 235 = 651261749 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 35011000094 and 35011000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35011000517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17505500058 + 17505500059.

It is an arithmetic number, because the mean of its divisors is an integer number (17505500059).

Almost surely, 235011000117 is an apocalyptic number.

It is an amenable number.

35011000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

35011000117 is an equidigital number, since it uses as much as digits as its factorization.

35011000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 105, while the sum is 19.

The spelling of 35011000117 in words is "thirty-five billion, eleven million, one hundred seventeen", and thus it is an aban number.