Base | Representation |
---|---|
bin | 1111111011010011110101… |
… | …11000110011000011100001 |
3 | 11121000012001202211012212111 |
4 | 13331221322320303003201 |
5 | 14042310031102303441 |
6 | 202253240352555321 |
7 | 10243226110631452 |
oct | 775517270630341 |
9 | 147005052735774 |
10 | 35023225041121 |
11 | 101832a2533779 |
12 | 3b1789b252b41 |
13 | 16708a30a67a5 |
14 | 8911c1481129 |
15 | 40b07b45e081 |
hex | 1fda7ae330e1 |
35023225041121 has 2 divisors, whose sum is σ = 35023225041122. Its totient is φ = 35023225041120.
The previous prime is 35023225041071. The next prime is 35023225041131. The reversal of 35023225041121 is 12114052232053.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 34846353486400 + 176871554721 = 5903080^2 + 420561^2 .
It is a cyclic number.
It is not a de Polignac number, because 35023225041121 - 223 = 35023216652513 is a prime.
It is not a weakly prime, because it can be changed into another prime (35023225041131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17511612520560 + 17511612520561.
It is an arithmetic number, because the mean of its divisors is an integer number (17511612520561).
Almost surely, 235023225041121 is an apocalyptic number.
It is an amenable number.
35023225041121 is a deficient number, since it is larger than the sum of its proper divisors (1).
35023225041121 is an equidigital number, since it uses as much as digits as its factorization.
35023225041121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 35023225041121 its reverse (12114052232053), we get a palindrome (47137277273174).
The spelling of 35023225041121 in words is "thirty-five trillion, twenty-three billion, two hundred twenty-five million, forty-one thousand, one hundred twenty-one".
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