3510404000141 has 2 divisors, whose sum is σ = 3510404000142. Its totient is φ = 3510404000140.

The previous prime is 3510404000101. The next prime is 3510404000161. The reversal of 3510404000141 is 1410004040153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1819288416100 + 1691115584041 = 1348810^2 + 1300429^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3510404000141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3510404000101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1755202000070 + 1755202000071.

It is an arithmetic number, because the mean of its divisors is an integer number (1755202000071).

Almost surely, 2^{3510404000141} is an apocalyptic number.

It is an amenable number.

3510404000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3510404000141 is an equidigital number, since it uses as much as digits as its factorization.

3510404000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 3510404000141 its reverse (1410004040153), we get a palindrome (4920408040294).

The spelling of 3510404000141 in words is "three trillion, five hundred ten billion, four hundred four million, one hundred forty-one", and thus it is an aban number.