351100121 has 2 divisors, whose sum is σ = 351100122. Its totient is φ = 351100120.

The previous prime is 351100109. The next prime is 351100147. The reversal of 351100121 is 121001153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 331422025 + 19678096 = 18205^2 + 4436^2 .

It is a cyclic number.

It is not a de Polignac number, because 351100121 - 2¹⁴ = 351083737 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 351100096 and 351100105.

It is not a weakly prime, because it can be changed into another prime (351100151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175550060 + 175550061.

It is an arithmetic number, because the mean of its divisors is an integer number (175550061).

Almost surely, 2^351100121 is an apocalyptic number.

It is an amenable number.

351100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

351100121 is an equidigital number, since it uses as much as digits as its factorization.

351100121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 14.

The square root of 351100121 is about 18737.6658364909. The cubic root of 351100121 is about 705.4674705897.

Adding to 351100121 its reverse (121001153), we get a palindrome (472101274).

The spelling of 351100121 in words is "three hundred fifty-one million, one hundred thousand, one hundred twenty-one".