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351125141 is a prime number
BaseRepresentation
bin10100111011011…
…011111010010101
3220110201000010212
4110323123322111
51204342001031
654501455205
711462341313
oct2473337225
9813630125
10351125141
11170223574
1299711505
135798b373
14348c10b3
1520c5c12b
hex14edbe95

351125141 has 2 divisors, whose sum is σ = 351125142. Its totient is φ = 351125140.

The previous prime is 351125119. The next prime is 351125161. The reversal of 351125141 is 141521153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 348905041 + 2220100 = 18679^2 + 1490^2 .

It is a cyclic number.

It is not a de Polignac number, because 351125141 - 26 = 351125077 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (351125161) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175562570 + 175562571.

It is an arithmetic number, because the mean of its divisors is an integer number (175562571).

Almost surely, 2351125141 is an apocalyptic number.

It is an amenable number.

351125141 is a deficient number, since it is larger than the sum of its proper divisors (1).

351125141 is an equidigital number, since it uses as much as digits as its factorization.

351125141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 600, while the sum is 23.

The square root of 351125141 is about 18738.3334637849. Note that the first 3 decimals coincide. The cubic root of 351125141 is about 705.4842278011.

Adding to 351125141 its reverse (141521153), we get a palindrome (492646294).

The spelling of 351125141 in words is "three hundred fifty-one million, one hundred twenty-five thousand, one hundred forty-one".