Base | Representation |
---|---|
bin | 100111111010110011110010… |
… | …0110100110111000101000001 |
3 | 1201001020201200100202001012112 |
4 | 1033311213210310313011001 |
5 | 332010404323401142400 |
6 | 3242443011054105105 |
7 | 133650220114202045 |
oct | 11765474464670501 |
9 | 1631221610661175 |
10 | 351130300412225 |
11 | a19765846a87a4 |
12 | 3346b4a31ab195 |
13 | 120c05a32ab759 |
14 | 629cb237d2025 |
15 | 2a8da89139835 |
hex | 13f59e4d37141 |
351130300412225 has 24 divisors (see below), whose sum is σ = 453112518317760. Its totient is φ = 269593827917120.
The previous prime is 351130300412197. The next prime is 351130300412261. The reversal of 351130300412225 is 522214003031153.
It is not a de Polignac number, because 351130300412225 - 26 = 351130300412161 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 351130300412191 and 351130300412200.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1449931787 + ... + 1450173936.
It is an arithmetic number, because the mean of its divisors is an integer number (18879688263240).
Almost surely, 2351130300412225 is an apocalyptic number.
It is an amenable number.
351130300412225 is a deficient number, since it is larger than the sum of its proper divisors (101982217905535).
351130300412225 is a wasteful number, since it uses less digits than its factorization.
351130300412225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2900105929 (or 2900105924 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 351130300412225 its reverse (522214003031153), we get a palindrome (873344303443378).
The spelling of 351130300412225 in words is "three hundred fifty-one trillion, one hundred thirty billion, three hundred million, four hundred twelve thousand, two hundred twenty-five".
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