Base | Representation |
---|---|
bin | 1111111101111011111001… |
… | …11101010101111110110001 |
3 | 11121022210221222201100020212 |
4 | 13332331330331111332301 |
5 | 14100244323222203101 |
6 | 202402521554513505 |
7 | 10252602061162355 |
oct | 776757475257661 |
9 | 147283858640225 |
10 | 35113454100401 |
11 | 10208594485456 |
12 | 3b31280895895 |
13 | 16792524b8ab1 |
14 | 895700967465 |
15 | 40d5ac9851bb |
hex | 1fef7cf55fb1 |
35113454100401 has 2 divisors, whose sum is σ = 35113454100402. Its totient is φ = 35113454100400.
The previous prime is 35113454100397. The next prime is 35113454100409. The reversal of 35113454100401 is 10400145431153.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 17698857414001 + 17414596686400 = 4207001^2 + 4173080^2 .
It is a cyclic number.
It is not a de Polignac number, because 35113454100401 - 22 = 35113454100397 is a prime.
It is not a weakly prime, because it can be changed into another prime (35113454100409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17556727050200 + 17556727050201.
It is an arithmetic number, because the mean of its divisors is an integer number (17556727050201).
Almost surely, 235113454100401 is an apocalyptic number.
It is an amenable number.
35113454100401 is a deficient number, since it is larger than the sum of its proper divisors (1).
35113454100401 is an equidigital number, since it uses as much as digits as its factorization.
35113454100401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 35113454100401 its reverse (10400145431153), we get a palindrome (45513599531554).
The spelling of 35113454100401 in words is "thirty-five trillion, one hundred thirteen billion, four hundred fifty-four million, one hundred thousand, four hundred one".
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