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35113454100401 is a prime number
BaseRepresentation
bin1111111101111011111001…
…11101010101111110110001
311121022210221222201100020212
413332331330331111332301
514100244323222203101
6202402521554513505
710252602061162355
oct776757475257661
9147283858640225
1035113454100401
1110208594485456
123b31280895895
1316792524b8ab1
14895700967465
1540d5ac9851bb
hex1fef7cf55fb1

35113454100401 has 2 divisors, whose sum is σ = 35113454100402. Its totient is φ = 35113454100400.

The previous prime is 35113454100397. The next prime is 35113454100409. The reversal of 35113454100401 is 10400145431153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17698857414001 + 17414596686400 = 4207001^2 + 4173080^2 .

It is a cyclic number.

It is not a de Polignac number, because 35113454100401 - 22 = 35113454100397 is a prime.

It is not a weakly prime, because it can be changed into another prime (35113454100409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17556727050200 + 17556727050201.

It is an arithmetic number, because the mean of its divisors is an integer number (17556727050201).

Almost surely, 235113454100401 is an apocalyptic number.

It is an amenable number.

35113454100401 is a deficient number, since it is larger than the sum of its proper divisors (1).

35113454100401 is an equidigital number, since it uses as much as digits as its factorization.

35113454100401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 35113454100401 its reverse (10400145431153), we get a palindrome (45513599531554).

The spelling of 35113454100401 in words is "thirty-five trillion, one hundred thirteen billion, four hundred fifty-four million, one hundred thousand, four hundred one".