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35121142341997 is a prime number
BaseRepresentation
bin1111111110001010001110…
…01101101010000101101101
311121100112210210111111000121
413333011013031222011231
514100411044414420442
6202410232520324541
710253263435151035
oct777050715520555
9147315723444017
1035121142341997
111021087a278128
123b32867613751
131679ba927508a
14895c2da7a8c5
1540d8ac8ec967
hex1ff14736a16d

35121142341997 has 2 divisors, whose sum is σ = 35121142341998. Its totient is φ = 35121142341996.

The previous prime is 35121142341953. The next prime is 35121142342037. The reversal of 35121142341997 is 79914324112153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23818831246116 + 11302311095881 = 4880454^2 + 3361891^2 .

It is a cyclic number.

It is not a de Polignac number, because 35121142341997 - 215 = 35121142309229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35121142341497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17560571170998 + 17560571170999.

It is an arithmetic number, because the mean of its divisors is an integer number (17560571170999).

Almost surely, 235121142341997 is an apocalyptic number.

It is an amenable number.

35121142341997 is a deficient number, since it is larger than the sum of its proper divisors (1).

35121142341997 is an equidigital number, since it uses as much as digits as its factorization.

35121142341997 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1632960, while the sum is 52.

The spelling of 35121142341997 in words is "thirty-five trillion, one hundred twenty-one billion, one hundred forty-two million, three hundred forty-one thousand, nine hundred ninety-seven".