Base | Representation |
---|---|
bin | 1111111110001010001110… |
… | …01101101010000101101101 |
3 | 11121100112210210111111000121 |
4 | 13333011013031222011231 |
5 | 14100411044414420442 |
6 | 202410232520324541 |
7 | 10253263435151035 |
oct | 777050715520555 |
9 | 147315723444017 |
10 | 35121142341997 |
11 | 1021087a278128 |
12 | 3b32867613751 |
13 | 1679ba927508a |
14 | 895c2da7a8c5 |
15 | 40d8ac8ec967 |
hex | 1ff14736a16d |
35121142341997 has 2 divisors, whose sum is σ = 35121142341998. Its totient is φ = 35121142341996.
The previous prime is 35121142341953. The next prime is 35121142342037. The reversal of 35121142341997 is 79914324112153.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23818831246116 + 11302311095881 = 4880454^2 + 3361891^2 .
It is a cyclic number.
It is not a de Polignac number, because 35121142341997 - 215 = 35121142309229 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35121142341497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17560571170998 + 17560571170999.
It is an arithmetic number, because the mean of its divisors is an integer number (17560571170999).
Almost surely, 235121142341997 is an apocalyptic number.
It is an amenable number.
35121142341997 is a deficient number, since it is larger than the sum of its proper divisors (1).
35121142341997 is an equidigital number, since it uses as much as digits as its factorization.
35121142341997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1632960, while the sum is 52.
The spelling of 35121142341997 in words is "thirty-five trillion, one hundred twenty-one billion, one hundred forty-two million, three hundred forty-one thousand, nine hundred ninety-seven".
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