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35124016117 is a prime number
BaseRepresentation
bin100000101101100011…
…011111001111110101
310100122212000220001211
4200231203133033311
51033413222003432
624045153321421
72352256132231
oct405543371765
9110585026054
1035124016117
11139946561a3
126982b66271
133409b258b8
1419b2b8d5c1
15da88cad47
hex82d8df3f5

35124016117 has 2 divisors, whose sum is σ = 35124016118. Its totient is φ = 35124016116.

The previous prime is 35124016097. The next prime is 35124016199. The reversal of 35124016117 is 71161042153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 35098523716 + 25492401 = 187346^2 + 5049^2 .

It is an emirp because it is prime and its reverse (71161042153) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35124016117 - 211 = 35124014069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35124016717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17562008058 + 17562008059.

It is an arithmetic number, because the mean of its divisors is an integer number (17562008059).

Almost surely, 235124016117 is an apocalyptic number.

It is an amenable number.

35124016117 is a deficient number, since it is larger than the sum of its proper divisors (1).

35124016117 is an equidigital number, since it uses as much as digits as its factorization.

35124016117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

The spelling of 35124016117 in words is "thirty-five billion, one hundred twenty-four million, sixteen thousand, one hundred seventeen".