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3513234240121 is a prime number
BaseRepresentation
bin110011000111111101000…
…101000011001001111001
3110102212021100001001012011
4303013331011003021321
5430030100431140441
611245542454245521
7511552135214044
oct63077505031171
913385240031164
103513234240121
111134a55158701
12488a7b0568a1
131c63b1734898
14c2081a1bc5b
15615c2148581
hex331fd143279

3513234240121 has 2 divisors, whose sum is σ = 3513234240122. Its totient is φ = 3513234240120.

The previous prime is 3513234240119. The next prime is 3513234240133. The reversal of 3513234240121 is 1210424323153.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2494014770025 + 1019219470096 = 1579245^2 + 1009564^2 .

It is a cyclic number.

It is not a de Polignac number, because 3513234240121 - 21 = 3513234240119 is a prime.

Together with 3513234240119, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3513234243121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1756617120060 + 1756617120061.

It is an arithmetic number, because the mean of its divisors is an integer number (1756617120061).

Almost surely, 23513234240121 is an apocalyptic number.

It is an amenable number.

3513234240121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3513234240121 is an equidigital number, since it uses as much as digits as its factorization.

3513234240121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 3513234240121 its reverse (1210424323153), we get a palindrome (4723658563274).

The spelling of 3513234240121 in words is "three trillion, five hundred thirteen billion, two hundred thirty-four million, two hundred forty thousand, one hundred twenty-one".