Base | Representation |
---|---|
bin | 1111111110100010011000… |
… | …10100111010000000001101 |
3 | 11121101210021202010201012101 |
4 | 13333101030110322000031 |
5 | 14101114130413431112 |
6 | 202420215543235101 |
7 | 10254233034164311 |
oct | 777211424720015 |
9 | 147353252121171 |
10 | 35134113030157 |
11 | 10216325952119 |
12 | 3b35287448a91 |
13 | 167b19555309b |
14 | 896700575b41 |
15 | 40ddbb4ae757 |
hex | 1ff44c53a00d |
35134113030157 has 2 divisors, whose sum is σ = 35134113030158. Its totient is φ = 35134113030156.
The previous prime is 35134113030109. The next prime is 35134113030197. The reversal of 35134113030157 is 75103031143153.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21709905853321 + 13424207176836 = 4659389^2 + 3663906^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35134113030157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35134113030197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17567056515078 + 17567056515079.
It is an arithmetic number, because the mean of its divisors is an integer number (17567056515079).
Almost surely, 235134113030157 is an apocalyptic number.
It is an amenable number.
35134113030157 is a deficient number, since it is larger than the sum of its proper divisors (1).
35134113030157 is an equidigital number, since it uses as much as digits as its factorization.
35134113030157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56700, while the sum is 37.
The spelling of 35134113030157 in words is "thirty-five trillion, one hundred thirty-four billion, one hundred thirteen million, thirty thousand, one hundred fifty-seven".
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