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351444431325661 is a prime number
BaseRepresentation
bin100111111101000110000100…
…0011111001100100111011101
31201002100202111200110211222221
41033322030020133030213131
5332031031143404410121
63243243202021505341
7134012010426666652
oct11772141037144735
91632322450424887
10351444431325661
11a1a87823389453
1233500350b72251
13121140b58946ab
1462b0003567c29
152a96d2218ab41
hex13fa3087cc9dd

351444431325661 has 2 divisors, whose sum is σ = 351444431325662. Its totient is φ = 351444431325660.

The previous prime is 351444431325601. The next prime is 351444431325671. The reversal of 351444431325661 is 166523134444153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 324421120749636 + 27023310576025 = 18011694^2 + 5198395^2 .

It is a cyclic number.

It is not a de Polignac number, because 351444431325661 - 233 = 351435841391069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 351444431325599 and 351444431325608.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (351444431325601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 175722215662830 + 175722215662831.

It is an arithmetic number, because the mean of its divisors is an integer number (175722215662831).

Almost surely, 2351444431325661 is an apocalyptic number.

It is an amenable number.

351444431325661 is a deficient number, since it is larger than the sum of its proper divisors (1).

351444431325661 is an equidigital number, since it uses as much as digits as its factorization.

351444431325661 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12441600, while the sum is 52.

The spelling of 351444431325661 in words is "three hundred fifty-one trillion, four hundred forty-four billion, four hundred thirty-one million, three hundred twenty-five thousand, six hundred sixty-one".