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35164897093 is a prime number
BaseRepresentation
bin100000101111111111…
…011011111101000101
310100202200221212020001
4200233333123331011
51034004203201333
624053213441301
72353263456604
oct405777337505
9110680855201
1035164897093
1113a05738727
1269947a0231
13341543a421
1419b8391a3b
15dac2a3b7d
hex82ffdbf45

35164897093 has 2 divisors, whose sum is σ = 35164897094. Its totient is φ = 35164897092.

The previous prime is 35164897037. The next prime is 35164897109. The reversal of 35164897093 is 39079846153.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21838041729 + 13326855364 = 147777^2 + 115442^2 .

It is an emirp because it is prime and its reverse (39079846153) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35164897093 - 213 = 35164888901 is a prime.

It is a super-2 number, since 2×351648970932 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35164891093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17582448546 + 17582448547.

It is an arithmetic number, because the mean of its divisors is an integer number (17582448547).

Almost surely, 235164897093 is an apocalyptic number.

It is an amenable number.

35164897093 is a deficient number, since it is larger than the sum of its proper divisors (1).

35164897093 is an equidigital number, since it uses as much as digits as its factorization.

35164897093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 55.

The spelling of 35164897093 in words is "thirty-five billion, one hundred sixty-four million, eight hundred ninety-seven thousand, ninety-three".