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35194853376013 is a prime number
BaseRepresentation
bin10000000000010011100001…
…01110111100000000001101
311121121121001211210222112111
420000021300232330000031
514103113024431013023
6202504143055504021
710261513163461612
oct1000116056740015
9147547054728474
1035194853376013
111023a065225a61
123b44bb9228011
131683b254a7736
148996234a6509
15410773c0400d
hex200270bbc00d

35194853376013 has 2 divisors, whose sum is σ = 35194853376014. Its totient is φ = 35194853376012.

The previous prime is 35194853375993. The next prime is 35194853376031. The reversal of 35194853376013 is 31067335849153.

Together with next prime (35194853376031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 32885660098404 + 2309193277609 = 5734602^2 + 1519603^2 .

It is an emirp because it is prime and its reverse (31067335849153) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35194853376013 - 233 = 35186263441421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35194853376413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17597426688006 + 17597426688007.

It is an arithmetic number, because the mean of its divisors is an integer number (17597426688007).

Almost surely, 235194853376013 is an apocalyptic number.

It is an amenable number.

35194853376013 is a deficient number, since it is larger than the sum of its proper divisors (1).

35194853376013 is an equidigital number, since it uses as much as digits as its factorization.

35194853376013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24494400, while the sum is 58.

The spelling of 35194853376013 in words is "thirty-five trillion, one hundred ninety-four billion, eight hundred fifty-three million, three hundred seventy-six thousand, thirteen".