Base | Representation |
---|---|
bin | 101000000010001100011111… |
… | …1100001011111001101100101 |
3 | 1201011211202220210022202211020 |
4 | 1100010120333201133031211 |
5 | 332124022322142422440 |
6 | 3244541213525201353 |
7 | 134113445066220045 |
oct | 12004307741371545 |
9 | 1634752823282736 |
10 | 352145434342245 |
11 | a2228049301275 |
12 | 335b4189560259 |
13 | 12165230a8686b |
14 | 62d5d03b63725 |
15 | 2aaa19e31d3d0 |
hex | 140463f85f365 |
352145434342245 has 128 divisors (see below), whose sum is σ = 583350461743104. Its totient is φ = 181299202473984.
The previous prime is 352145434342243. The next prime is 352145434342249. The reversal of 352145434342245 is 542243434541253.
It is not a de Polignac number, because 352145434342245 - 21 = 352145434342243 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (352145434342243) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 20469992814 + ... + 20470010016.
It is an arithmetic number, because the mean of its divisors is an integer number (4557425482368).
Almost surely, 2352145434342245 is an apocalyptic number.
It is an amenable number.
352145434342245 is a deficient number, since it is larger than the sum of its proper divisors (231205027400859).
352145434342245 is a wasteful number, since it uses less digits than its factorization.
352145434342245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18611.
The product of its digits is 27648000, while the sum is 51.
Adding to 352145434342245 its reverse (542243434541253), we get a palindrome (894388868883498).
The spelling of 352145434342245 in words is "three hundred fifty-two trillion, one hundred forty-five billion, four hundred thirty-four million, three hundred forty-two thousand, two hundred forty-five".
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