Base | Representation |
---|---|
bin | 10000000001010101101110… |
… | …11110100100100111001011 |
3 | 11121201222211011001220200012 |
4 | 20000222313132210213023 |
5 | 14104203324400202403 |
6 | 202532342231302135 |
7 | 10264212104034254 |
oct | 1000526736444713 |
9 | 147658734056605 |
10 | 35230400006603 |
11 | 1025314639270a |
12 | 3b4ba7981a94b |
13 | 168729ba2c069 |
14 | 89b236425b2b |
15 | 41165475ded8 |
hex | 200ab77a49cb |
35230400006603 has 2 divisors, whose sum is σ = 35230400006604. Its totient is φ = 35230400006602.
The previous prime is 35230400006591. The next prime is 35230400006611. The reversal of 35230400006603 is 30660000403253.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 35230400006603 - 218 = 35230399744459 is a prime.
It is a super-4 number, since 4×352304000066034 (a number of 55 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 35230400006603.
It is not a weakly prime, because it can be changed into another prime (35230400006903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17615200003301 + 17615200003302.
It is an arithmetic number, because the mean of its divisors is an integer number (17615200003302).
Almost surely, 235230400006603 is an apocalyptic number.
35230400006603 is a deficient number, since it is larger than the sum of its proper divisors (1).
35230400006603 is an equidigital number, since it uses as much as digits as its factorization.
35230400006603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 32.
Adding to 35230400006603 its reverse (30660000403253), we get a palindrome (65890400409856).
The spelling of 35230400006603 in words is "thirty-five trillion, two hundred thirty billion, four hundred million, six thousand, six hundred three".
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