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352414606414253 is a prime number
BaseRepresentation
bin101000000100001001110101…
…1011011011101000110101101
31201012210111200212001210111112
41100020103223123131012231
5332142430103220224003
63245305011333001405
7134142054322121345
oct12010235333350655
91635714625053445
10352414606414253
11a2321216988a29
123363838a783265
1312184729b3c656
146304d5a901d25
152ab21a53613d8
hex14084eb6dd1ad

352414606414253 has 2 divisors, whose sum is σ = 352414606414254. Its totient is φ = 352414606414252.

The previous prime is 352414606414133. The next prime is 352414606414267.

352414606414253 is nontrivially palindromic in base 10.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 222563521984969 + 129851084429284 = 14918563^2 + 11395222^2 .

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 352414606414253 - 230 = 352413532672429 is a prime.

It is a super-2 number, since 2×3524146064142532 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (352414606414753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176207303207126 + 176207303207127.

It is an arithmetic number, because the mean of its divisors is an integer number (176207303207127).

Almost surely, 2352414606414253 is an apocalyptic number.

It is an amenable number.

352414606414253 is a deficient number, since it is larger than the sum of its proper divisors (1).

352414606414253 is an equidigital number, since it uses as much as digits as its factorization.

352414606414253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8294400, while the sum is 50.

The spelling of 352414606414253 in words is "three hundred fifty-two trillion, four hundred fourteen billion, six hundred six million, four hundred fourteen thousand, two hundred fifty-three".