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352534133453 is a prime number
BaseRepresentation
bin1010010000101001010…
…10111111101011001101
31020200221201011111221112
411020110222333223031
521233442214232303
6425541341541405
734320060456305
oct5102452775315
91220851144845
10352534133453
11126566367317
12583a6b74865
13273228bc288
14130c424a605
1592847730d8
hex5214abfacd

352534133453 has 2 divisors, whose sum is σ = 352534133454. Its totient is φ = 352534133452.

The previous prime is 352534133423. The next prime is 352534133467. The reversal of 352534133453 is 354331435253.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 352524812644 + 9320809 = 593738^2 + 3053^2 .

It is an emirp because it is prime and its reverse (354331435253) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 352534133453 - 212 = 352534129357 is a prime.

It is a super-2 number, since 2×3525341334532 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 352534133453.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (352534133423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176267066726 + 176267066727.

It is an arithmetic number, because the mean of its divisors is an integer number (176267066727).

Almost surely, 2352534133453 is an apocalyptic number.

It is an amenable number.

352534133453 is a deficient number, since it is larger than the sum of its proper divisors (1).

352534133453 is an equidigital number, since it uses as much as digits as its factorization.

352534133453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972000, while the sum is 41.

The spelling of 352534133453 in words is "three hundred fifty-two billion, five hundred thirty-four million, one hundred thirty-three thousand, four hundred fifty-three".