Search a number
-
+
35254371141481 is a prime number
BaseRepresentation
bin10000000010000010011000…
…10001001100011101101001
311121211021200201222201212111
420001001030101030131221
514110101423003011411
6202551345020042321
710266021116234002
oct1001011421143551
9147737621881774
1035254371141481
1110262327480088
123b546496933a1
13168961c05cb3b
1489c46bcaa1a9
154120a8e4c721
hex20104c44c769

35254371141481 has 2 divisors, whose sum is σ = 35254371141482. Its totient is φ = 35254371141480.

The previous prime is 35254371141469. The next prime is 35254371141557. The reversal of 35254371141481 is 18414117345253.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 25290247581481 + 9964123560000 = 5028941^2 + 3156600^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35254371141481 is a prime.

It is a super-2 number, since 2×352543711414812 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (35254371141421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17627185570740 + 17627185570741.

It is an arithmetic number, because the mean of its divisors is an integer number (17627185570741).

Almost surely, 235254371141481 is an apocalyptic number.

It is an amenable number.

35254371141481 is a deficient number, since it is larger than the sum of its proper divisors (1).

35254371141481 is an equidigital number, since it uses as much as digits as its factorization.

35254371141481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1612800, while the sum is 49.

The spelling of 35254371141481 in words is "thirty-five trillion, two hundred fifty-four billion, three hundred seventy-one million, one hundred forty-one thousand, four hundred eighty-one".