Base | Representation |
---|---|
bin | 10000000010000010011000… |
… | …10001001100011100101101 |
3 | 11121211021200201222201210021 |
4 | 20001001030101030130231 |
5 | 14110101423003011141 |
6 | 202551345020042141 |
7 | 10266021116233555 |
oct | 1001011421143455 |
9 | 147737621881707 |
10 | 35254371141421 |
11 | 10262327480033 |
12 | 3b54649693351 |
13 | 168961c05cac3 |
14 | 89c46bcaa165 |
15 | 4120a8e4c6d1 |
hex | 20104c44c72d |
35254371141421 has 2 divisors, whose sum is σ = 35254371141422. Its totient is φ = 35254371141420.
The previous prime is 35254371141403. The next prime is 35254371141469. The reversal of 35254371141421 is 12414117345253.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 34792467408196 + 461903733225 = 5898514^2 + 679635^2 .
It is a cyclic number.
It is not a de Polignac number, because 35254371141421 - 211 = 35254371139373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35254371141481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17627185570710 + 17627185570711.
It is an arithmetic number, because the mean of its divisors is an integer number (17627185570711).
Almost surely, 235254371141421 is an apocalyptic number.
It is an amenable number.
35254371141421 is a deficient number, since it is larger than the sum of its proper divisors (1).
35254371141421 is an equidigital number, since it uses as much as digits as its factorization.
35254371141421 is an evil number, because the sum of its binary digits is even.
The product of its digits is 403200, while the sum is 43.
Adding to 35254371141421 its reverse (12414117345253), we get a palindrome (47668488486674).
The spelling of 35254371141421 in words is "thirty-five trillion, two hundred fifty-four billion, three hundred seventy-one million, one hundred forty-one thousand, four hundred twenty-one".
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