Base | Representation |
---|---|
bin | 100000111000110101… |
… | …111110000001010011 |
3 | 10101011001102002210221 |
4 | 200320311332001103 |
5 | 1034310213111011 |
6 | 24120040533511 |
7 | 2360046014326 |
oct | 407065760123 |
9 | 111131362727 |
10 | 35313410131 |
11 | 13a8155477a |
12 | 6a16481297 |
13 | 343a13856c |
14 | 19cddb07bd |
15 | dba33c971 |
hex | 838d7e053 |
35313410131 has 2 divisors, whose sum is σ = 35313410132. Its totient is φ = 35313410130.
The previous prime is 35313410087. The next prime is 35313410137. The reversal of 35313410131 is 13101431353.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 35313410131 - 221 = 35311312979 is a prime.
It is a super-2 number, since 2×353134101312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 35313410096 and 35313410105.
It is not a weakly prime, because it can be changed into another prime (35313410137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17656705065 + 17656705066.
It is an arithmetic number, because the mean of its divisors is an integer number (17656705066).
Almost surely, 235313410131 is an apocalyptic number.
35313410131 is a deficient number, since it is larger than the sum of its proper divisors (1).
35313410131 is an equidigital number, since it uses as much as digits as its factorization.
35313410131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 35313410131 its reverse (13101431353), we get a palindrome (48414841484).
The spelling of 35313410131 in words is "thirty-five billion, three hundred thirteen million, four hundred ten thousand, one hundred thirty-one".
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