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3534010492121 is a prime number
BaseRepresentation
bin110011011011010011011…
…100001010010011011001
3110111211220021012222222222
4303123103130022103121
5430400123141221441
611303300233353425
7513216034355234
oct63332334122331
913454807188888
103534010492121
1111428468782aa
12490ab8b68875
131c8342b99015
14c309304a41b
1561ddb0e9d4b
hex336d370a4d9

3534010492121 has 2 divisors, whose sum is σ = 3534010492122. Its totient is φ = 3534010492120.

The previous prime is 3534010492097. The next prime is 3534010492141. The reversal of 3534010492121 is 1212940104353.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3066071040400 + 467939451721 = 1751020^2 + 684061^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3534010492121 is a prime.

It is not a weakly prime, because it can be changed into another prime (3534010492141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1767005246060 + 1767005246061.

It is an arithmetic number, because the mean of its divisors is an integer number (1767005246061).

Almost surely, 23534010492121 is an apocalyptic number.

It is an amenable number.

3534010492121 is a deficient number, since it is larger than the sum of its proper divisors (1).

3534010492121 is an equidigital number, since it uses as much as digits as its factorization.

3534010492121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 3534010492121 its reverse (1212940104353), we get a palindrome (4746950596474).

The spelling of 3534010492121 in words is "three trillion, five hundred thirty-four billion, ten million, four hundred ninety-two thousand, one hundred twenty-one".