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35352055631413 is a prime number
BaseRepresentation
bin10000000100111000010101…
…01101111100111000110101
311122011121211112120222110001
420002130022231330320311
514113202002220201123
6203104302105431301
710306046615552203
oct1002341255747065
9148147745528401
1035352055631413
111029a7a48611a4
123b6b56ba9b531
1316958b8c26881
148a30975c2073
154148c4c500ad
hex20270ab7ce35

35352055631413 has 2 divisors, whose sum is σ = 35352055631414. Its totient is φ = 35352055631412.

The previous prime is 35352055631351. The next prime is 35352055631419. The reversal of 35352055631413 is 31413655025353.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35114904163089 + 237151468324 = 5925783^2 + 486982^2 .

It is an emirp because it is prime and its reverse (31413655025353) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35352055631413 - 245 = 167683542581 is a prime.

It is a super-2 number, since 2×353520556314132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35352055631419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17676027815706 + 17676027815707.

It is an arithmetic number, because the mean of its divisors is an integer number (17676027815707).

Almost surely, 235352055631413 is an apocalyptic number.

It is an amenable number.

35352055631413 is a deficient number, since it is larger than the sum of its proper divisors (1).

35352055631413 is an equidigital number, since it uses as much as digits as its factorization.

35352055631413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2430000, while the sum is 46.

The spelling of 35352055631413 in words is "thirty-five trillion, three hundred fifty-two billion, fifty-five million, six hundred thirty-one thousand, four hundred thirteen".