3540000001 has 2 divisors, whose sum is σ = 3540000002. Its totient is φ = 3540000000.

The previous prime is 3539999999. The next prime is 3540000011. The reversal of 3540000001 is 1000000453.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2225574976 + 1314425025 = 47176^2 + 36255^2 .

It is an emirp because it is prime and its reverse (1000000453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3540000001 - 2¹ = 3539999999 is a prime.

Together with 3539999999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (3540000011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1770000000 + 1770000001.

It is an arithmetic number, because the mean of its divisors is an integer number (1770000001).

Almost surely, 2^3540000001 is an apocalyptic number.

It is an amenable number.

3540000001 is a deficient number, since it is larger than the sum of its proper divisors (1).

3540000001 is an equidigital number, since it uses as much as digits as its factorization.

3540000001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 3540000001 is about 59497.8991309777. The cubic root of 3540000001 is about 1524.0565697124.

Adding to 3540000001 its reverse (1000000453), we get a palindrome (4540000454).

The spelling of 3540000001 in words is "three billion, five hundred forty million, one", and thus it is an aban number.