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354148722017 is a prime number
BaseRepresentation
bin1010010011101001110…
…10001010010101100001
31020212010020022010001222
411021310322022111201
521300244033101032
6430405500104425
734405064316506
oct5116472122541
91225106263058
10354148722017
111272147a2632
1258777835115
132751c26231c
14131d885b4ad
15932b3a4a12
hex5274e8a561

354148722017 has 2 divisors, whose sum is σ = 354148722018. Its totient is φ = 354148722016.

The previous prime is 354148721917. The next prime is 354148722019. The reversal of 354148722017 is 710227841453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 342563213521 + 11585508496 = 585289^2 + 107636^2 .

It is a cyclic number.

It is not a de Polignac number, because 354148722017 - 210 = 354148720993 is a prime.

Together with 354148722019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (354148722019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177074361008 + 177074361009.

It is an arithmetic number, because the mean of its divisors is an integer number (177074361009).

Almost surely, 2354148722017 is an apocalyptic number.

It is an amenable number.

354148722017 is a deficient number, since it is larger than the sum of its proper divisors (1).

354148722017 is an equidigital number, since it uses as much as digits as its factorization.

354148722017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 376320, while the sum is 44.

The spelling of 354148722017 in words is "three hundred fifty-four billion, one hundred forty-eight million, seven hundred twenty-two thousand, seventeen".