Base | Representation |
---|---|
bin | 110011100010010001111… |
… | …010100101000000001101 |
3 | 110112120020022010111221210 |
4 | 303202101322211000031 |
5 | 431010443240313031 |
6 | 11310535415245033 |
7 | 513602461461240 |
oct | 63422172450015 |
9 | 13476208114853 |
10 | 3541501104141 |
11 | 1145a40056a50 |
12 | 492449679779 |
13 | 1c8c67a1ac20 |
14 | c35a3bd7257 |
15 | 621c8a25746 |
hex | 33891ea500d |
3541501104141 has 128 divisors (see below), whose sum is σ = 6561903882240. Its totient is φ = 1638849945600.
The previous prime is 3541501104133. The next prime is 3541501104173. The reversal of 3541501104141 is 1414011051453.
It is not a de Polignac number, because 3541501104141 - 23 = 3541501104133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3541501104099 and 3541501104108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3541501104941) by changing a digit.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 197939806 + ... + 197957696.
It is an arithmetic number, because the mean of its divisors is an integer number (51264874080).
Almost surely, 23541501104141 is an apocalyptic number.
It is an amenable number.
3541501104141 is a deficient number, since it is larger than the sum of its proper divisors (3020402778099).
3541501104141 is a wasteful number, since it uses less digits than its factorization.
3541501104141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20227.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 3541501104141 its reverse (1414011051453), we get a palindrome (4955512155594).
The spelling of 3541501104141 in words is "three trillion, five hundred forty-one billion, five hundred one million, one hundred four thousand, one hundred forty-one".
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