354200531411 has 2 divisors, whose sum is σ = 354200531412. Its totient is φ = 354200531410.

The previous prime is 354200531327. The next prime is 354200531413. The reversal of 354200531411 is 114135002453.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-354200531411 is a prime.

It is a super-3 number, since 3×354200531411³ (a number of 36 digits) contains 333 as substring.

Together with 354200531413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (354200531413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177100265705 + 177100265706.

It is an arithmetic number, because the mean of its divisors is an integer number (177100265706).

Almost surely, 2^354200531411 is an apocalyptic number.

354200531411 is a deficient number, since it is larger than the sum of its proper divisors (1).

354200531411 is an equidigital number, since it uses as much as digits as its factorization.

354200531411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 354200531411 its reverse (114135002453), we get a palindrome (468335533864).

The spelling of 354200531411 in words is "three hundred fifty-four billion, two hundred million, five hundred thirty-one thousand, four hundred eleven".