Base | Representation |
---|---|
bin | 1010010011110000000… |
… | …00101000101110100011 |
3 | 1020212020212012110102202 |
4 | 11021320000220232203 |
5 | 21300400343013021 |
6 | 430414555203415 |
7 | 34406265464522 |
oct | 5117000505643 |
9 | 1225225173382 |
10 | 354200751011 |
11 | 1272410a97a8 |
12 | 5879114656b |
13 | 27529c7b103 |
14 | 132017224b9 |
15 | 9330c30a0b |
hex | 5278028ba3 |
354200751011 has 2 divisors, whose sum is σ = 354200751012. Its totient is φ = 354200751010.
The previous prime is 354200750999. The next prime is 354200751013. The reversal of 354200751011 is 110157002453.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-354200751011 is a prime.
It is a super-3 number, since 3×3542007510113 (a number of 36 digits) contains 333 as substring.
It is a Sophie Germain prime.
Together with 354200751013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (354200751013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177100375505 + 177100375506.
It is an arithmetic number, because the mean of its divisors is an integer number (177100375506).
Almost surely, 2354200751011 is an apocalyptic number.
354200751011 is a deficient number, since it is larger than the sum of its proper divisors (1).
354200751011 is an equidigital number, since it uses as much as digits as its factorization.
354200751011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 29.
Adding to 354200751011 its reverse (110157002453), we get a palindrome (464357753464).
The spelling of 354200751011 in words is "three hundred fifty-four billion, two hundred million, seven hundred fifty-one thousand, eleven".
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