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35420351413 is a prime number
BaseRepresentation
bin100000111111001101…
…111010101110110101
310101102111122021200011
4200333031322232311
51040020102221123
624134421020221
72362515006436
oct407715725665
9111374567604
1035420351413
11140269572a7
126a46254671
13345633c625
141a0028b48d
15dc4913e0d
hex83f37abb5

35420351413 has 2 divisors, whose sum is σ = 35420351414. Its totient is φ = 35420351412.

The previous prime is 35420351363. The next prime is 35420351443. The reversal of 35420351413 is 31415302453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25421751364 + 9998600049 = 159442^2 + 99993^2 .

It is an emirp because it is prime and its reverse (31415302453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 35420351413 - 213 = 35420343221 is a prime.

It is a super-3 number, since 3×354203514133 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35420351443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17710175706 + 17710175707.

It is an arithmetic number, because the mean of its divisors is an integer number (17710175707).

Almost surely, 235420351413 is an apocalyptic number.

It is an amenable number.

35420351413 is a deficient number, since it is larger than the sum of its proper divisors (1).

35420351413 is an equidigital number, since it uses as much as digits as its factorization.

35420351413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 35420351413 its reverse (31415302453), we get a palindrome (66835653866).

The spelling of 35420351413 in words is "thirty-five billion, four hundred twenty million, three hundred fifty-one thousand, four hundred thirteen".