35420520014531 has 2 divisors, whose sum is σ = 35420520014532. Its totient is φ = 35420520014530.

The previous prime is 35420520014527. The next prime is 35420520014533. The reversal of 35420520014531 is 13541002502453.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 35420520014531 - 2² = 35420520014527 is a prime.

It is a super-3 number, since 3×35420520014531³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 35420520014533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 35420520014491 and 35420520014500.

It is not a weakly prime, because it can be changed into another prime (35420520014533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17710260007265 + 17710260007266.

It is an arithmetic number, because the mean of its divisors is an integer number (17710260007266).

Almost surely, 2^{35420520014531} is an apocalyptic number.

35420520014531 is a deficient number, since it is larger than the sum of its proper divisors (1).

35420520014531 is an equidigital number, since it uses as much as digits as its factorization.

35420520014531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 35420520014531 its reverse (13541002502453), we get a palindrome (48961522516984).

The spelling of 35420520014531 in words is "thirty-five trillion, four hundred twenty billion, five hundred twenty million, fourteen thousand, five hundred thirty-one".