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35420646334013 is a prime number
BaseRepresentation
bin10000000110111000000110…
…00010101101111000111101
311122102011212202002200201122
420003130003002231320331
514120312440430142023
6203200004214320325
710314025431114113
oct1003340302557075
9148364782080648
1035420646334013
11103168a2494276
123b809129590a5
13169c1ca3b8925
148a6522d85ab3
1541658b7812c8
hex2037030ade3d

35420646334013 has 2 divisors, whose sum is σ = 35420646334014. Its totient is φ = 35420646334012.

The previous prime is 35420646333913. The next prime is 35420646334079. The reversal of 35420646334013 is 31043364602453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 34630435566169 + 790210767844 = 5884763^2 + 888938^2 .

It is a cyclic number.

It is not a de Polignac number, because 35420646334013 - 210 = 35420646332989 is a prime.

It is a super-3 number, since 3×354206463340133 (a number of 42 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35420646364013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17710323167006 + 17710323167007.

It is an arithmetic number, because the mean of its divisors is an integer number (17710323167007).

Almost surely, 235420646334013 is an apocalyptic number.

It is an amenable number.

35420646334013 is a deficient number, since it is larger than the sum of its proper divisors (1).

35420646334013 is an equidigital number, since it uses as much as digits as its factorization.

35420646334013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1866240, while the sum is 44.

The spelling of 35420646334013 in words is "thirty-five trillion, four hundred twenty billion, six hundred forty-six million, three hundred thirty-four thousand, thirteen".